Question 847083
a){{{R1=180000+100*t}}}
{{{R2=80*t}}}
Find {{{t}}} when {{{R1>=R2}}}
{{{180000+100*t=80*t}}}
{{{20t=-180000}}}
{{{t=-9000}}}
Since we start time at t=0, R1 will always be greater than R2.
There is no breakeven point.
b) R2 is always less costly.