Question 71296
The standard form of the equation of a circle is:
{{{highlight((x-h)^2+(y-k)^2=r^2)}}}, where (h,k)=center and r=radius
Give the equation for the circle with center c(3,-2) and radius 4.
(h,k)=(3,-2) and r=4
{{{(x-3)^2+(y-(-2))^2=4^2}}}
{{{highlight((x-3)^2+(y+2)^2=16)}}}
Happy Calculating!!!!