Question 847001
{{{ (2/3)*y = (1/9)*x + 2 }}}
Multiply both sides by {{{ 9 }}}
{{{ 6y = x + 18 }}}
subtract {{{ 6y }}} from both sides
{{{ 0 = x - 6y + 18 }}}
subtract {{{ 18 }}} from both sides
{{{ -18 = x - 6y }}}
Now write it in the reverse order:
{{{ x - 6y = -18 }}}
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check the answer:
Let {{{ x = 9 }}}
{{{ (2/3)*y = (1/9)*9 + 2 }}}
{{{ (2/3)*y = 3 }}}
{{{ y = 9/2 }}}
and
{{{ x - 6y = -18 }}}
{{{ 9 - 6y = -18 }}}
{{{ -6y = -18 - 9 }}}
{{{ -6y = -27 }}}
{{{ y = 9/2 }}}
OK