Question 846558
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
{{{log(4,(-2h)) = 7}}}
 4^7 = -2h
16384 = -2h
-8192 = h

*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]   Applied
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]