Question 846553
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
6 - radical x+2 =x+2
Let s = {{{sqrt(x+2)}}} &#8658; 
 6 -s = s^2
 s^2 + s - 6 = 0  Factor to find solutions
(s+3)(s-2) = 0,  s = -3 (extraneous)  0r s = 2   
 s = {{{sqrt(x+2)}}}  
   2= {{{sqrt(x+2)}}}  x = 2
0r s^2 = 4 = x+2 ,  x = 2
CHECKING our answer***
 6 - 2 = 4
Wish You the Best in your Studies.