Question 846485
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Hi,
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure 
p = .34,  n = 5
TI or long hand
P(x=2) = binompdf(n, p, x-value)= binompdf(5, .34, 2)  Or 5C2 {{{(.34)^2*(.66)^3}}} = 10{{{(.34)^2*(.66)^3}}}
P(x =0)= binompdf(n, p, x-value)= binompdf(5, .34, 0)  0r {{{(.34)^0*(.66)^5}}}
P(x =5)= binompdf(n, p, x-value)= binompdf(5, .34, 5) 0r {{{(.34)^5*(.66)^0}}}
P(x &#8805; 1) = 1 -binomcdf(n, p, largest x-value) =  1 -binomcdf(5 .34. 0)