Question 846462
{{{A}}}= volume of mixture A
{{{B}}}= volume of product B in mixture A
{{{C}}}= volume of product C in mixture A
Mixture A is made of 58% of product B and 42% of product C.
We assume that volumes are additive (or very nearly so),
meaning that {{{A=B+C}}} .
B is 58% of A, so {{{B=(58/100)*A}}} or {{{B=0.58A}}}
C is 42% of A, so {{{C=(42/100)*A}}} or {{{C=0.42A}}}
 
With {{{B=0.58A}}} and {{{C=0.42A}}} ,
given any one of the volumes, you can calculate the other two volumes.
If you know {{{B}}} ,
{{{B=0.58A}}} --> {{{B/0.58=A}}} --> {{{highlight(A=B/0.58)}}} .
Then,
{{{system(C=0.42A,A=B/0.58)}}} --> {{{C=0.42(B/0.58)}}} --> {{{highlight(C=0.42*B/0.58)}}} or {{{highlight(C=(42/58)*B)}}}
That can be calculated as approximately {{{C=0.724*B)}}} .