Question 846138
How many liters of each .5% saline solution and 2% saline to produce 10 liters of .9% saline?
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let x=amt of .5% solution
10-x=amt of 2% solution
..
.5%x+2%(10-x)=.9%*10
.005x+.02(10-x)=.009*10
.005x+.20-.02x=.09
.015x=110
x=110/.015=22/3
10-x=30/3-22/3=8/3
amt of .5% solution=22/3 liters
amt of 2% solution=8/3 liters