Question 846162
 log(sub5)(x+10)+log(sub5)(x-10)=3
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log5[(x+10)(x-10)] = 3
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x^2-100 = 5^3 = 125
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x^2 = 25
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x = 5 or x = -5
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Both are extraneous solutions
because both values would make
x-10 negative.  And you can't
have the log of a negative.
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Ans: No solution::
Cheers,
Stan H.