Question 846158
When {{{2x-3>0}}},{{{2x>3}}}, {{{x>3/2}}} then 
{{{f(x)=2x-2x+3}}}
{{{f(x)=3}}}
When {{{2x-3<0}}}, {{{x<3/2}}} then
{{{f(x)=2x+2x-3}}}
{{{f(x)=4x-3}}}
{{{graph(300,300,-5,5,-5,5,2x-abs(2x-3))}}}
So then {{{f(x)=4x-3}}}for ({{{-infinity}}},{{{3/2}}}) and {{{f(x)=3}}} for ({{{3/2}}},{{{infinity}}})