Question 71059
Solve for x:
{{{ a/(x-3a) }}}= {{{b/(x+3b)}}}
:
Cross multiply and you have:
b(x-3a) = a(x+3b)
:
bx - 3ab = ax + 3ab; multiplied what's inside the brackets
:
bx - ax = 3ab + 3ab; subtracted ax, and added 3ab to both sides
:
x(b - a) = 6ab; factored out x
:
x = {{{(6ab)/((b-a))}}}; divided both sides by (b-a)