Question 845818
find the remaining trigonometric functions of theta if: sin theta =2/3 is in Q1
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By definition, sin = y/r, so y = 2 and r = 3
Then x = sqrt[3^2-2^2] = sqrt(5)
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sin = y/r = 2/3
cos = x/r = sqrt(5)/3
tan = y/x = 2/sqrt(3)
csc = 3/2
sec = 3/sqrt(5)
cot = sqrt(3)/2
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Cheers,
Stan H.
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