Question 846032
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Hi,
The factor theorem states that a polynomial f(x) has a factor (x &#8722; k) if and only if f(k) = 0.
k being a 'solution' 
{{{ s(s+3)=0 }}}
 s = {{{ highlight_green(0)}}}  0r (s+3) = 0, s = {{{ highlight_green(-3)}}}   | {{{0*3 = 0}}}. {{{(-3+3) = 0}}}
{{{ 4a(a-6)=0 }}}
 4a = 0, a = {{{ highlight_green(0)}}}  0r (a-6) = 0, a = {{{ highlight_green(6)}}}  | {{{4*0 = 0}}}. {{{(6-6) = 0}}}
{{{ 3m(m+5)=0 }}}
 3m = 0, m = {{{ highlight_green(0)}}}  0r (m+5) = 0, m = {{{ highlight_green(-5)}}} | {{{3*0 = 0}}}. {{{(-5+5) = 0}}}