Question 845925
Since the current adds to his speed and
then subtracts the same amount, you can
disregard the current
{{{ d = r*t }}}
Convert 15 min to hrs ( time to swim downstream )
{{{ 15*( 1/60 ) = 1/4 }}} hrs
{{{ d = 3*(1/4) }}}
{{{ d = 3/4 }}} km downstream