Question 845448
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
2^x*4^-y=2
{{{2^x*(2^2)^(-y) = 2^1}}}
{{{2^x*2^(-2y) = 2^1}}}  &#8658; {{{ highlight_green(x - 2y = 1)}}}
3^-x*9^2y=3
{{{3^(-x)*3^(4y) = 2^1}}}  &#8658; {{{ highlight_green(-x+4y = 1)}}}
 x-2y = 1
<u>-x+4y = 1</u>
     2y = 2
      y = 1   and x = 3

CHECKING our answer*** {{{2^x*4^(-y)=2}}}
{{{2^3*4^(-1)=2}}}
 8/4 = 2
Wish You the Best in your Studies.

{{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}} *** Applied
{{{root(a,p)*root(a,q) = root(a,p*q)}}}  
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}***Applied
{{{root(n, (x/y)) = root(n,x)/root(n,y)}}}
{{{(xy)^n = x^n*y^n}}}
{{{x^(1/n) = root(n,x)}}}   , {{{x^(m/n) = (root(n,x))^m}}}