Question 845397
It's please, first off.
{{{P^2=3+13P}}}
{{{P^2-13P-3=0}}}
Use the quadratic formula,
{{{P = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{P = (-(-13) +- sqrt( (-13)^2-4*1*(-3) ))/(2*1) }}} 
{{{P = (13 +- sqrt( 169+12 ))/(2) }}} 
{{{P = (13 +- sqrt(181) )/(2) }}}