Question 845449
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Hi,
NOte:  2log 2 + log 7 = log 2^2 + log7 = log 28
     log 28 = {{{2*.301 + .845 = 1.447 }}}

*[tex \large\ \ nlog_bx = log_b(x^n) ] *** Applied
*[tex \large\ \ log_bx + log_by = log_b(xy) ]*** Applied
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]