<PRE><B>Question 845342</B>
Let the amount invested at 7% be x, then the amount invested at 2% is 16000-x.
no of years = 1

SI at 2% = (16000-x)* 1*2/100 = (32000-2x)/100
SI at 7% = (x)*1*7/100 = 7x)/100
SI at 2% + SI at 7% = 970
(32000-2x)/100 + 7x/100 = 970
(32000-2x+7x)/100 = 970
5x+32000 = 97000
5x = 97000-32000
5x = 65000
x = 13000
amount invested at 7%= 13000 and amount invested at 2% = 16000 - 13000 = 3000

</PRE>