Question 845222
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Hi,
the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry
The standard form is {{{(x -h)^2 = 4p(y -k)}}}, where  the focus is (h,k + p)
With Directrix y = -(k+p)
focus (0,6) and directrix y= -10,  p = {{{(6-(-10))/2 = 8}}}  4p = 32
  y = (1/32)x^2 -2
{{{drawing(300,300,   -20,20,-20,20,  
 grid(1),
circle(0, 6,0.4),
circle(0, -1,0.4),
graph( 300, 300, -20,20,-20,20,0,-10, (1/32)x^2 -2))}}}