Question 845109
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Hi,
IF
{{{1/(x-2) - 2/x(x-2) = 3}}}  |Multiplying thru by x(x-2) so as all denominators = 1
   x - 2 = 3x(x-2)
     3x^2 - 6x - x + 2 = 0
     3x^2 - 7x + 2 = 0
   (3x-1)(x-2) = 0,  x = 1/3           |Note: x = 2 (extraneous solution)