Question 845014
{{{(19*pi)/4=(19*pi)/4-(8*pi)/4-(8*pi)/4=(3/4)pi}}}

{{{cos((3/4)pi)=-sqrt(2)/2}}}
{{{sin((3/4)pi)=sqrt(2)/2}}}
{{{tan((3/4)pi)=-1}}}
You can get the other three by taking reciprocals.