Question 844880
First substitute, {{{u=sqrt(x)}}},{{{u^2=x}}}
{{{3u^2+5u-2=0}}}
{{{(3u-1)(u+2)=0}}}
Two possible solutions:
{{{3u-1=0}}}
{{{3u=1}}}
{{{u=1/3}}}
{{{sqrt(x)=1/3}}}
{{{x=1/9}}}
and
{{{u+2=0}}}
{{{u=-2}}}
{{{sqrt(x)=-2}}}
This is not a solution.
Only {{{x=1/9}}}.