Question 844869
(x+2, 2y-3)=(0,1) ---> x+2 = 0 and 2y-3 = 1


x+2 = 0


x = -2


-----------


2y -3 = 1


2y = 1+3


2y = 4


y = 4/2


y = 2


So (x,y) = (-2, 2)