Question 844838
The line {{{ y = 4 }}} is a horizontal line through
( x, 4 ) where x can be any number
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The point ( 2, 3 ) is 1 unit below this line
The perpendicular from ( 2, 3 ) intersects the
line at ( 2, 4 )
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Call {{{ a }}} the distance from ( 2, 4 ) to the point
where the distance from ( 2,3 ) is 5 units
{{{ a^2 = 5^2 - 1^2 }}}
{{{ a^2 = 25 - 1 }}}
{{{ a = sqrt( 24 ) }}}
{{{ a = 2*sqrt(6) }}}
{{{ a = 2.4495 }}} 
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The points that are 5 units from (2,3) are:
( 2 + a, 4 ) and
( 2 - a, 4 )
{{{ 2 + a = 4.4495 }}}
{{{ 2 - a = -.4495 }}}
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( 4.4495, 4 ) and
( -.4495, 4 )
answers
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Hope I got it