Question 844719
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Hi,
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
log a=2 &#8658;   10^2 = a, {{{sqrt(a) = 10}}}
log b=3 &#8658;   10^3 = b,  {{{b^3 = 10^6}}}
{{{log(10, (sqrt(a)/b^3) )= log(10,  (10/10^(6))) = -5}}}