Question 844693
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Hi,
The length of a rectangle is 11 more than twice the width {{{ highlight_green(x) }}}
A = {{{l*w)}}}
(2x+11)x = 63m^2
 2x^2 + 11x - 63 = 0
(2x -7)(x+ 9) = 0,   x = 7/2  (Tossing out the negative solution for unit measure)
 width is 3.5m   and length is 18m             {{{2(7/2) + 11}}}
CHECKING our answer***
{{{(3.5m)(18m) = 63 m^2}}}
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