Question 844593
{{{x-8=-11}}} --> {{{x=-11+8}}} --> {{{x=-3}}}
There are no restrictions on {{{y}}} so {{{y}}} can equal any number.
The graph for the linear equation {{{x-8=-11}}} is the vertical line
{{{drawing(300,300,-6,4,-4,6,
grid(0),green(line(-3,-5,-3,6)),
circle(-3,4,0.1),circle(-3,-1,0.1),
locate(-2.95,3.95,P(-3,4)),locate(-2.95,-1.05,Q(-3,4))
)}}} All the points have {{{x=-3}} , and any {{{y}}} value they want.
So the answer is {{{highlight(D)}}} , the only pair of points (P and Q) that both have {{{-3}}} for their x-coordinate