Question 844576
Call the surface {{{ y = 0 }}} 
Call {{{ 97 }}} m below the surface {{{ y = -97 }}}
and {{{ t = 0 }}} where {{{ t }}} is time in minutes
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Plot {{{ y }}} on the vertical axis
Plot {{{ t }}} on the horizontal axis
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The rate of change of the diver's depth is
a positive {{{ 5 }}} m/min
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The linear equation for the diver is:
{{{ y = 5t - 97 }}}
Notice that when {{{ t=0 }}}, {{{ y = -97 }}}
as it should
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When {{{ t = 10 }}} min
{{{ y = 5*10 - 97 }}}
{{{ y = 50 - 97 }}}
{{{ y = -47 }}}
The diver is 47 m below the surface