Question 844451
{{{2x+3y>18}}}
{{{3y>-2x+18}}}
{{{y>-(2/3)x+6}}}
First graph {{{y=-(2/3)x+6}}}
{{{graph(300,300,-10,10,-10,10,-(2/3)x+6)}}}
Then choose a point not on the line.
(0,0) is a convenient choice.
Test it in the inequality.
{{{2(0)+3(0)>18}}}
{{{0>18}}}
So (0,0) is not in the solution region.
Shade the area that doesn't contain (0,0).
{{{graph(300,300,-10,10,-10,10,y>-(2/3)x+6)}}}