Question 844453
Manipulate the equation into the slope intercept form.  y = mx + b where m is the slope.<P>
3x-2y + 4=0<P>
-2y=-3x + -4
y = (3/2)x + +2.  The slope is 3/2. <P>
Parallel Lines have the same slope.  Perpendicular lines have slopes that are negative reciprocals.   y-y1 = m(x-x1) is the equation of a line passing through the point (x1,y1)<P>
Parallel: slope is 3/2: y-4 = 3/2 (x-3)<P>
y-4 = (3/2)x - 9/2<P>
y = (3/2)x -1/2<P>
Perpendicular: slope is -2/3<P>
y-4 = -2/3 (x-3)<P>
y-4 = (-2/3)x +2<P>
y= (-2/3)x +6