Question 71148
Solve for x:
{{{5/(2x+3) + 1/(x-6) = 0}}} Add the two fractions on the left side.  The common denominator is :{{{(2x+3)*(x-6)}}}
Multiply the first fraction by {{{(x-6)/(x-6)}}} and the second fraction by: {{{(2x+3)/(2x+3)}}}
{{{(5(x-6)+(2x+3))/((2x+3)*(x-6)) = 0}}} Now multiply both sides by {{{(2x+3)*(x-6)}}}
{{{5(x-6)+(2x+3) = 0}}} Simplify.
{{{5x-30+2x+3 = 0}}}
{{{7x-27 = 0}}} Add 27 to both sides.
{{{7x = 27}}} Divide both sides by 7.
{{{x = 27/7}}} or x = 3 6/7