Question 844234
Call the smaller number {{{ n }}}
The larger number will be {{{ n + 2 }}}
{{{ (1/3)*n = (1/7)*( n + 2 ) + 6 }}}
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{{{ (1/3 )*n = ( 1/7 )*n + 2/7 + 6 }}}
Multiply both sides by {{{ 21 }}}
{{{ 7n = 3n + 6 + 126 }}}
{{{ 4n = 132 }}}
{{{ n = 33 }}}
{{{ n + 2 = 35 }}}
The consecutive odd numbers are 33 and 35
check:
{{{ (1/3)*n = (1/7)*( n + 2 ) + 6 }}}
{{{ (1/3)*33 = (1/7)*35 + 6 }}}
Multiply both sides by {{{21}}}
{{{ 7*33 = 3*35 + 126 }}}
{{{ 231 = 105 + 126 }}}
{{{ 231 = 231 }}}
OK