Question 844180
Look at the possible two item draws and their probabilities.
(G,G)={{{(11/15)(11/15)=121/225}}}
(G,D)={{{(11/15)(4/15)=44/225}}}
(D,G)={{{(4/15)(11/15)=44/225}}}
(D,D)={{{(4/15)(4/15)=16/225}}}
If you sum all of the probabilities, you will get 1.
The one you want has a probability of {{{P=44/225}}}