Question 844168
The square plot is x by x.  Diagonal is d, and let's form {{{d^2=x^2+x^2}}}, which is according to Pythagorean Theorem.  {{{d=sqrt(2x^2)}}}, {{{highlight_green(d=x*sqrt(2))}}}.


Area of the square plot would be {{{x^2}}}.  Will you use this?


Rectangular plot is 45 by 40 meter*meter, so this area is {{{45*40=1800}}} square meters.


Back to the square plot.  The description means that {{{highlight_green(x^2=1800)}}} and we want to use {{{highlight_green(d=x*sqrt(2))}}}.
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We want to find d as our answer.
{{{x=sqrt(1800)}}}, which you should try to use in its simplified form.
{{{d=sqrt(1800)*sqrt(2)}}}, 
{{{sqrt(2*1800)}}}
{{{sqrt(3600)}}}
{{{sqrt(6*6*100)}}}
Final result, {{{highlight(d=60)}}}