Question 71133
4X^2+70X=-150
4X^2+70X+150=0 the process here is that you have to factor both the 4 & the 150 so that the sum of the products = 70. thus the factors of 4 are 1&4, 2&2. the factors of 150 are 1&150, 2&75, 3&50, 5&30, 6&25, 10&15. 
examples of the sum of products are: 2*2+2*75=4+150=154, 1*6+4*25=6+100=106,
2*10+2*15=20+30=50 & 1*10+4*15=10+60=70 which is the pair of factors you want. 
hope this explains what needs to be done. it is a trial & error process or you could use the quadratic equation:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}  
(4X+10)(X+15)=0 
4X+10=0
4X=-10
X=-10/4
X=-2.5 ANSWER
X+15=0
X=-15 ANSWER