Question 844079
One root of a quadratic equation is "3+2i". Determine the other root and write the equation that has these values as its roots.
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Other root: 3-2i
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Equation:
f(x) = (x-(3+2i))(x-(3-2i))
Rearrange:
f(x) = ((x-3)-2i)((x-3)+2i)
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f(x) = (x-3)^2+4
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f(x) = x^2 - 6x +13
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Cheers,
Stan H.