Question 844022
Write an arithmetic series with seven terms such that 
the sum of the series is 64.
Let the 1st term be "a";
Then the 7th term is a + 6d
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S(7) = (7/2)(a+(a+6d)) = 64
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7(2a+6d) = 128
7(a+3d) = 64
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7a+21d = 64
a + 3d = 9.1429
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Let a = 0.1426
Then d = 3
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0.1429,3.1429,6.1429,9.1429,12.1429,15.1429,18.1429
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Cheers,
Stan H.
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