Question 843961
Multiply eq. 1 by 2 and add to eq. 2,
{{{-4x+14y+4x-14y=-14+14}}}
{{{0=0}}}
Eq. 1 and eq. 2 are the same equation. In other words they are the same line. 
If you multiply eq. 1 by -2 you get eq. 2, as we saw.
There are infinitely many solutions. 
{{{graph(300,300,-5,5,-5,5,(4x-14)/14),(2x-7)/7}}}