Question 843783
You didn't use parentheses so I'm guessing here.
{{{2/(2x+4)=-12/4x}}}
{{{1/(x+2)=-3x}}}
{{{1=-3x(x+2)}}}
{{{1=-3x^2-6x}}}
{{{3x^2+6x+1=0}}}
{{{3(x^2+2x+1)-2=0}}}
{{{3(x+1)^2=2}}}
{{{(x+1)^2=2/3}}}
{{{x+1=0 +- sqrt(2/3)}}}
{{{x=-1 +- sqrt(2/3)}}}
{{{x=-1 +- sqrt(6)/3}}}