Question 843889
A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age.
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let x=son's present age
2x=father's present age
..
12 years ago:
x-12=son's age
2x-12= father's age
2x-12=4(x-12)
2x-12=4x-48
2x=36
x=18
2x=36
son's present age=18
father's present age=36