Question 843356
Let's find the probability that both are blue since P(both blue)+P(both not blue)=1.
I'm assuming it's without replacement.
{{{P(1B)=7/(8+7+5)=7/20}}}
and the second,
{{{P(2B)=6/19}}}
So then 
{{{P(B,B)=(7/20)(6/19)=(7/10)(3/19)=21/190}}}
So then the probability we want is,
{{{P=1-21/190=190/190-21/190=169/190}}}