<PRE><B>Question 71056</B>
 Three consecutive integers
x, x+1, x+2
:
the first plus one-half the second plus seven less than twice the third is 2101.
x + .5(x+1) + 2(x+2) - 7 = 2101
:
What are the integers?
x + .5x + .5 + 2x + 4 - 7 = 2101
:
x + .5x + 2x + .5 + 4 - 7 = 2101
:
3.5x - 2.5 = 2101
:
3.5x = 2101 + 2.5
:
x = 2103.5/3.5
:
x = 601 is the 1st integer
:
Check: 
601 + .5(602 + 2(603) - 7 =
601 + 301 + 1206 - 7 = 2101


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