Question 843242
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Hi,
How many gallons {{{highlight_green(x)}}} of a 90% antifreeze solution must be mixed 
with 90 gallons of 30% antifreeze to get a mixture that is 80% antifreeze?
   .90x + .30(90gal) = .80(90gal + x)
          x =  .50(90gal)/.10 = 450gal