Question 843229
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Hi,
 complement of an angle {{{highlight_green(x)}}} is 12 degrees less than one-fifth of its supplement
Question states***
{{{(90-x) = (1/5)(180-x)-12}}}   |Multiplying thru by 5 so as all denominators = 1
 5(90°-x) = (180°-x) - 60°
 450° - 5x = 180° - x - 60°
     330° = 4x
     82.5° = x