Question 71085
5y=-x+1
y=-x/5+1/5 thus a line perpendicular to this line has a slope of 5 & passes through(2,-5)
-5=5*2+b
-5=10+b
b=-5-10
b=-15 
so the equation for this line is 
y=5x-15
here is the graph of these two lines
{{{ graph( 400, 400, -16, 16, -16, 16,y = -x/5 +1/5, y = 5x -15) }}} (graph 400x400 pixels, x from -16 to 16, y from -16 to 16, of TWO functions y = -x/5 +1/5 and y = 5x -15).