Question 842871
{{{lim(x->0,sin(x)/x)=1}}}
So then,
{{{lim(x->0,sin^2(x)/x^2)=1^2=1}}}
and
{{{lim(x->0,tan(x)/x)=lim(x->0,(sin(x)/x)*(1/cos(x)))=1*1=1}}}
so then
{{{lim(x->0,tan^2(x)/x^2)=1^2=1}}}
and finally
{{{lim(x->0,(sin^2(x)+tan^2(x))/x^2)=1+1=2}}}