Question 843064
Look at all of the possible outcomes. 
111 
112
113
.
.
.
665
666
There are {{{6^3}}} or {{{216}}} of them.
Three of a kind outcomes are {111,222,333,444,555,666}. 
There are 6 of those.
{{{P(3 of a kind)=6/216=1/36}}}
.
.
.
When you sum the numbers, half of the 216 sum to even, half sum to odd.
{{{P(odd)=108/216=1/2}}}
So to sum the probability of 3 of a kind or sum that's odd, add the probabilities. Remember to remove the 3 of a kind sums that are odd (111,333,555) so you don't count those twice (3/216 outcomes). 
{{{P=6/216+108/216-3/216=111/216}}}