Question 9297
i think your equation is written incorrectly, but you have the correct answer.


Let width of square = w

so, rectangle length = w+5


Area of square = {{{w^2}}}
Area of rectangle = w(w+5) --> {{{w^2 + 5w}}}


together these areas equal 133, so {{{w^2 + 5w + w^2 = 133}}}


{{{2w^2 + 5w = 133}}}
{{{2w^2 + 5w - 133 = 0}}}
(2w+19)(w-7) = 0


so ignoring the first bracket, as this gives a negative answer, we have w=7.


so square is 7x7
and rectangle is 7x12.


jon.