Question 842910
{{{x^2+2x-3=(x+3)(x-1)}}}
{{{x^2-x-2=(x-2)(x+1)}}}
So then,
{{{((x^2+2x-3)/(x^2-x-2))*((x-2)/(x+3))=(((x+3)(x-1))/((x-2)(x+1)))*((x-2)/(x+3))}}}
{{{((x^2+2x-3)/(x^2-x-2))*((x-2)/(x+3))=(x-1)/(x+1)}}}