Question 842901

{{{(x^2-6x+5)/(x^2-3x-10)=((x-1)(x-5))/((x-5)(x+2))}}}
{{{(x^2-6x+5)/(x^2-3x-10)=(x-1)/(x+2)}}}
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{{{x}}} cannot equal {{{-2}}} because this would cause a division by zero.